在扩展类时，以任何方式访问特定于方法的变量是不是类的属性？

Question

Pleace consider the following example:

class A {
    public method() {
        $foo = 'bar';
    }
}

class B extends A {
    public method {
        parent::method();
        echo $foo; // $foo == null
    }
}

I run to situations like this quite frequently when I need to extend the functionality of a class coded by somebody else. Is there a way to have the $foo of the aforementioned example to be not null but bar?

I know perfectly well, that what I'm suggesting is not a problem at all if the variable $foo were a property of the class. However, this example applies to a situation where the class I want to extend is poorly designed and modifying the original class and changing the rogue variables into class properties is out of the question for reasons such as the class being a part of a CMS and update compatibility etc.

Answer 1

Unfortunately not. Once method() is called, the $foo variable is contained only within method(). You would have to change method() to either return $foo, or echo it itself. Once method() completes its run (which is quick, as all it does is create a variable), that local variable is then destroyed.