douweng7308 2014-08-12 07:15
浏览 7
已采纳

无法使用PHP脚本更新表

I have written a php-script to update a table. Please refer to the the following code:

<?php

/*
 * Following code will update view-status of seen queries
 * limit value is read from HTTP Post Request
 */

// array for JSON response
$response = array();

// check for required fields
if (isset($_POST['limit'])) 
{

    $limit = $_POST['limit'];

    //echo "limit= " . $limit;
    // include db connect class
    require_once __DIR__ . '/db_connect.php';

    // connecting to db
    $db = new DB_CONNECT();

    $con = mysqli_connect(DB_SERVER, DB_USER, DB_PASSWORD, DB_DATABASE);

    if (mysqli_connect_errno()) 
    {
       echo "Failed to connect to MySQL: " . mysqli_connect_error();
    }
    // mysql Updating view_status
    $result=mysqli_query($con,"UPDATE tbl_query_master t1 INNER JOIN (SELECT query_id FROM tbl_query_master WHERE view_status=0 ORDER BY query_date ASC LIMIT '".$limit."') as t2 on t1.query_id = t2.query_id SET t1.view_status=1");

    if($result)
    {
      // Record updated successfully
      $response["success"] = 1;
      $response["message"] = "Updated successfully.";
    }
   else
   {
        // Record updated successfully
      $response["success"] = 0;
      $response["message"] = "Oops! An error occurred.";
   }

     // echoing JSON response
     echo json_encode($response);
}
else 
{
    // required field is missing
    $response["success"] = 0;
    $response["message"] = "Required field(s) is missing";

    // echoing JSON response
    echo json_encode($response);
}
?>

But for some unknown reason my update query above is not working and is giving me the following error:

"{"success":0,"message":"Oops! An error occurred."}"

However, if I execute following query manually then it works perfectly.

  UPDATE tbl_query_master t1 
  INNER JOIN (SELECT query_id 
  FROM tbl_query_master WHERE view_status=0 
  ORDER BY query_date ASC LIMIT 2) as t2 
  on t1.query_id = t2.query_id SET t1.view_status=1;
  • 写回答

3条回答 默认 最新

  • dongshang1768 2014-08-12 07:27
    关注

    Try to change string

    $result=mysqli_query($con,"UPDATE tbl_query_master t1 INNER JOIN (SELECT query_id FROM tbl_query_master WHERE view_status=0 ORDER BY query_date ASC LIMIT '".$limit."') as t2 on t1.query_id = t2.query_id SET t1.view_status=1");
    

    to

    $result=mysqli_query($con,"UPDATE tbl_query_master t1 INNER JOIN (SELECT query_id FROM tbl_query_master WHERE view_status=0 ORDER BY query_date ASC LIMIT ".$limit.") as t2 on t1.query_id = t2.query_id SET t1.view_status=1");
    

    You don't need single quotes around $limit value.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(2条)

报告相同问题?

悬赏问题

  • ¥15 孟德尔随机化结果不一致
  • ¥15 apm2.8飞控罗盘bad health,加速度计校准失败
  • ¥15 求解O-S方程的特征值问题给出边界层布拉休斯平行流的中性曲线
  • ¥15 谁有desed数据集呀
  • ¥20 手写数字识别运行c仿真时,程序报错错误代码sim211-100
  • ¥15 关于#hadoop#的问题
  • ¥15 (标签-Python|关键词-socket)
  • ¥15 keil里为什么main.c定义的函数在it.c调用不了
  • ¥50 切换TabTip键盘的输入法
  • ¥15 可否在不同线程中调用封装数据库操作的类