dotxxh0998 2014-03-12 21:03
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防止在扩展类中使用类名作为构造函数

Check out this example:

class ParentClass {
    public function __construct() {
        // Does not prevent using 'SomeObject' as constructor
    }
}

class SomeObject extends ParentClass {
    function SomeObject () {
        // Should not use this as constructor
    }
}

$obj = new SomeObject();

How can I prevent for each extending class to use the class name as the constructor? I've tried to set an empty __construct, but it still calls the SomeObject-Method (what is actually logical).

Is there a way to disable it in the php.ini or in a similar way as I tried above? I googled about 2 hours but I couldn't find anything.

Greets

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  • douhao9203 2014-03-12 21:16
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    You can try making function SomeObject private:

    private function SomeObject()
    

    It is weird, though. According to the documentation the old style constructor should not be called at all when your class contains a __construct or when it descends from another class that has a __construct. So if you are really sure this happens, maybe you can file a bug report.

    [edit] As per request, I tested this locally on PHP 5.4.3. I can confirm that the old style constructor is indeed called. To my feeling this contradicts with this statement:

    For backwards compatibility, if PHP 5 cannot find a __construct() function for a given class, and the class did not inherit one from a parent class, it will search for the old-style constructor function, by the name of the class.

    In this case, the class does inherit a __construct() function, so PHP should not search for the old constructor.

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