douyalin2258 2014-10-09 20:27
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PHPunit设置referer

I have code like the below that I want to test

class Controller_test{
    public function action_index(){
        if(!$this->referred_from_site()){
            echo "Un-authorized request";
            return;
        }
        echo "Request OK";
    }
    public function referred_from_site(){
        if(strpos($this->request->referrer(),$_SERVER['HTTP_HOST']) !== FALSE ){
            return TRUE;
        } 
        return FALSE;
    }
}

Now, in PHPUnit script I can set the value of $_SERVER['HTTP_HOST'] from setUP() function. But, how to set value for $this->request->referrer()? or how to do it if I want to set the value of function referred_from_site() as TRUE?

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1条回答 默认 最新

  • 普通网友 2014-10-10 01:19
    关注

    It is a function but not a parameter. I suggest that if you want to set it, use a private variable. Something like this.

    class Controller_test{
        private referred = false;
    
        public function action_index(){
            if(!$this->referred){
                echo "Un-authorized request";
                return;
            }
            echo "Request OK";
        }
    
        public function referred_from_site(){
            if(strpos($this->request->referrer(),$_SERVER['HTTP_HOST']) !== FALSE ){
                $this->referred = TRUE;
            } 
            $this->referred = FALSE;
        }
    }
    

    And by the way, I don't think it is a good idea to change the value of $_SERVER['HTTP_HOST'], just use another parameter such as $server = $_SERVER and mess with it like $server['HTTP_HOST'] = 'domain'

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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