doushi1473
2013-06-11 16:55
浏览 45
已采纳

CodeIgniter将参数传递给CORE MY_Controller中的函数

I hope that this is possible

Can I pass parameters to functions in CORE/MY_Controller?

I am developing a application that has three controllers and most of the functions are the same so I want to code functions ones and use them again in their respectable controllers when need.

function like search_User_Name() will be in both of the controllers, it will be cool if i can get to code it once and reuse it. the problems that i am facing at the moment are

  1. The MY_Controller.php is not in the same folders as other controllers
  2. The search_User_Name() function has to receive parameters like search_User_Name($var1, $var2)

I have a controller in the core folder as MY_Controller

class MY_Controller extends CI_Controller{

    public function __construct() {
             parent::__construct();
    }

    public function Testing($var){
     $function_var= $var;
     return $function_var;
   }
}

and i have a controller in the controller folder as Sub_Controlller

class Sub_Controller extends MY_Controller{
    public function __construct() {
        parent::__construct();
    }

    public function Show(){
        echo($this->Testing());
    }
}

on the view i have

echo anchor('Sub_Controller/Show/Parameter','Pass a parameter');

according to my understanding i was spouse to get the word "parameter" on the screen. can any help?

  • 点赞
  • 写回答
  • 关注问题
  • 收藏
  • 邀请回答

1条回答 默认 最新

  • dsbqfrr098575666 2013-06-11 17:05
    已采纳

    It will work fine, but you still need to pass in the arguments:

    class Sub_Controller extends MY_Controller {
        public function Show($arg = null) {
            echo($this->Testing($arg));
        }
    }
    

    Alternatively you can read the URI segment from the base function, but then you have less control:

    class MY_Controller extends CI_Controller {
        public function Testing() {
            $function_var = $this->uri->segment(2);
            return $function_var;
       }
    }
    class Sub_Controller extends MY_Controller {
        public function Show() {
            echo($this->Testing()); // prints the argument in the URL
        }
    }
    

    Better to do it the first way.

    点赞 打赏 评论

相关推荐 更多相似问题