drbz99867
2019-05-26 04:52
浏览 155
已采纳

str_replace函数无法替换多个值[重复]

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I have set of strings and need to replace them using str)replace as we loop through the query as the query is success need to replace each value in PHP.

<?php

include_once("con.php");
$db = new Da();

$con = $db->con();

$lclString = "{{ONE}} {{TWO}} {{THREE}} {{FOUR}} {{FIVE}} {{SIX}}";

 $lclCount = 1;
 if(preg_match_all("/\{\{[^{}]+\}\}/", $lclString, $matches)) {

    foreach ($matches[0] as $match) {

        $lclQuery = "SELECT link, link_value FROM student WHERE link_value = '".$match."'";

        $lclResult = $connString->query($lclQuery);

        while($row = $lclResult->fetch(PDO::FETCH_ASSOC)) {

            $lclNewValue = str_replace($match, $row['link'], $lclString);

            }

        }

        echo json_encode($NewValue);

 } 

?>

Here only second replacement is happening.

</div>
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1条回答 默认 最新

  • dsf5632 2019-05-26 05:01
    已采纳
    <?php
    
    include_once("con.php");
    $db = new Da();
    
    $con = $db->con();
    
    $lclString = "{{ONE}} {{TWO}} {{THREE}} {{FOUR}} {{FIVE}} {{SIX}}";
    
     $lclCount = 1;
     if(preg_match_all("/\{\{[^{}]+\}\}/", $lclString, $matches)) {
     $lclNewValue = $lclString;
    foreach ($matches[0] as $match) {
    
        $lclQuery = "SELECT link, link_value FROM student WHERE link_value = '".$match."'";
    
        $lclResult = $connString->query($lclQuery);
    
        while($row = $lclResult->fetch(PDO::FETCH_ASSOC)) {
    
            $lclNewValue = str_replace($match, $row['link'], $lclNewValue);
    
            }
    
        }
    
        echo json_encode($NewValue);
    
     } 
    
    ?>
    
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