douyuan1752
2019-03-11 03:26
浏览 80

JSON语法与AJAX调用和jquery每个循环

I have an AJAX call that returns the data from PHP

echo json_encode( $json_response);

and the result is as follows

[{"name":"Sprouts.......}]

I then loop through it with JQUERY

$.each($.parseJSON(data), function(i, obj) {
         var name = (obj.name);
         var address = (obj.address);        
        });

This works perfectly fine, but I am trying to add a name (child) to it so that I can have other children. I used the following

json_encode(array('storedata' => $json_response))

to add the name storedata which returns

{"storedata":[{"name":"Sprouts....

I have tried looping through with

$.each($.parseJSON(data.storedata), function(i, obj) {
             var name = (obj.name);
             var address = (obj.address);        
            });

but something is wrong with the syntax because the data.storedata is undefined.

What is the correct syntax and/or correct way to do this. Thank you for any and all help.

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1条回答 默认 最新

  • donglu8779 2019-03-11 04:10
    已采纳

    The problem is that you are trying to access storedata before parsing the string into an object, so you need to replace $.parseJSON(data.storedata) with $.parseJSON(data).storedata:

    $.each($.parseJSON(data).storedata, function(i, obj) {
             var name = (obj.name);
             var address = (obj.address);        
            });
    
    已采纳该答案
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