dongyan3237 2016-09-09 14:25
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SQL - 更改现有行

I'm using PHP in order to create a website where managers have access and review forms that employees have submitted. In the reviewing PHP file, I have created two buttons which basically approve or disapprove the form. After they click on one of the buttons, they are being redirected to another PHP file which actually inserts into the MySQL Database a change in a column I named 'processed'. It changes 0 which is unprocessed to 1, which is processed. The table I am referring to has columns such as formid, fullname, department and other job related stuff, as well as the 'processed' column which allows the managers to see if there is a pending form to be reviewed.

My problem is that I have no idea how to actually allow MySQL to find the proper row and change only the cell with the name 'processed' from 0 to 1 without having to insert every cell again. Here's what I have tried till now:

$id = $_SESSION[id];
$fullname = $_SESSION[fullname];
$teamformid = $_SESSION[teamformid];

if (isset($_POST['approved'])) {
    $sql = "INSERT INTO carforms (processed) where aboveid='$id' and processed='0' and teamformid=$teamformid
    VALUES ('0')";
}

else if (isset($_POST['disapproved'])) {
    //todo
}

How do I tell SQL to only find the specific row I want and change only one column which is processed?

Also, do I always have to type every column name when I use the INSERT INTO command?

Thanks in advance.

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  • dongtaihui5131 2016-09-09 14:38
    关注

    Use the Below code it'll work for you.

    $id = $_SESSION[id];
    $fullname = $_SESSION[fullname];
    $teamformid = $_SESSION[teamformid];
    
    if (isset($_POST['approved'])) {
        $sql = "UPDATE `carforms` SET processed = '1' WHERE `aboveid` = '".$id."' AND `teamformid` = '".$teamformid."'";
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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