douchou8935 2016-08-25 12:33
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php sqlsrv - 字段未更新

i want to update two fields from a table called Leave Request but when i click on the submit button.

 <?php 
$stmt = $pdo->prepare('UPDATE dbo.[TABLE$Leave Request] dbo.[KPMG$Leave Request].supAprrove_date=?,dbo.[TABLE$Leave Request].supAprrove=? WHERE     dbo.[TABLE$Leave Request].id=?');
$stmt->execute(array($adate, $approve, $id));

$adate = $_POST['supAprrove_date'];
 $approve =$_POST['supAprrove'];
$id = $_POST['lid'];
 //$affected_rows = $stmt->rowCount();

?>
<form id="form1" name="form1" method="post" action="pending_leave.php">
  <label>
  <select name="supAprrove" id="supAprrove">
    <option value="1">Approve</option>
    <option value="2">Reject</option>
  </select>
  </label>
  <input name="supAprrove_date" type="hidden" id="supAprrove_date" value="<?php echo date('Y-m-d'); ?>" />
  <input type="hidden" name="lid" id="lid"  value="<?php echo $data['id'];  ?>"/>
  <label>
  <input type="submit" name="button" id="button" value="Submit" />
  </label>
</form>
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1条回答 默认 最新

  • duanmajing9332 2016-08-25 12:51
    关注

    The one way to create a SQL UPDATE statement is

    UPDATE table
    SET column1 = expression1,
    column2 = expression2,
    ...
    [WHERE conditions];
    

    Example:

    UPDATE employees
    SET last_name = 'Johnson'
    WHERE employee_id = 10;
    

    You are using prepared statements so replace the 'Johnson' part with "?" and you are done.

    For error handling you can use:

    $dbh = new PDO($dsn, $user, $password, array(PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION));
    

    The part PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION is the key to throw exceptions.

    More on PDO error handling: http://php.net/manual/en/pdo.error-handling.php

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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