Json Parse问题与错误尝试获取非对象的属性

Question

I want to parse following json for value of

JSON (saved in my.json):

{
"mackoniv":{"entry":"","lastExit":"","userId":"OPENGOVTJOBS","userNick":"mack"},
"johanna":{"entry":"","lastExit":"","userId":"FREEJOBALERT","userNick":"jone"}
}

Code used :

$json = file_get_contents('my.json');
$json_data = json_decode($json,true);
$userToCheck='johanna';
echo 'userId'.$json_data->$userToCheck->userId;

The above code gives error "Trying to get property of non-object", which i understand as $userToCheck isnt an object of $json_data but how do i access the data of "mackoniv" or even "johanna" when userToCheck part is not to be hardcoded.

If i try following way, it gives same error.

echo 'userId'.$json_data[$userToCheck]['userId'];

Answer 1

first of all json_decode($jsondata, true); would return an array. try to var_dump your $json to make sure you've got the file and then var_dump $json_data.