I am aware that this is probably a very trivial problem which I just can't seem to get right although I have spent the last few hours crawling the web..
I have a file image_get.php which is supposed to display an image file "keepcalm.png" that is located in the same directory as the php file.
I am using a class to handle all the image related actions.
image_get.php
<?php
include "classes/image.class.php";
include "classes/database.class.php";
$database_sso = new database('SSO'); //will be needed later and is dummy for now
$testimage = new image($database_sso, "1"); //parameters are dummy for now
$testimage->show_image();
?>
image.class.php
<?php
class image{
private $database_image; //Image Database containing all images
private $imageid; //ID of Image in Database
private $filepath; //Path to image file
//PUBLIC FUNCTIONS
public function __construct($database, $imageid){
$this->database_image = $database; //Right now this is just a placeholder
$this->imageid = $imageid; //Right now this is just a placeholder
}
public function show_image(){
$remoteImage = $this->get_local_link_from_id($this->imageid); // Right now this returns "keepcalm.png"
header('Content-Type: image/x-png')
$returnstring = readfile($remoteImage);
}
//PRIVATE FUNCTIONS
private function get_local_link_from_id($imageid){
$local_link = "keepcalm.png"; //dummy for now
return $local_link;
}
}
?>
The output I get is complet gibberish as can be seen here -> http://niederrad.no-ip.org/portal/image_get.php
What am I missing? I have tried lots of iterations of the above and am completely clueless as to how I should proceed..
