dsdtszi0520538 2012-10-20 15:32 采纳率: 100%
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SQL查询其中值小于数字

Ok i need to select from database banks wich have the minimum <= 50 and than show the names of the banks and their tarifs. I did it like this but it doesn't work.

$result = mysql_query("SELECT * FROM list1 WHERE minimum <= 50]");

while($row = mysql_fetch_array($result))
  {
  echo $row['bank_name'] . " - " . $row['Tarif'];
  echo "<br />";
  }
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1条回答 默认 最新

  • dongtang5776 2012-10-20 15:46
    关注
    $result = mysql_query("SELECT * FROM list1 WHERE minimum <= 50]");
                                                                  ^---typo
    

    If you had the following construct, you'd have gotten the error message:

    $result = mysql_query(yada yada) or die(mysql_error());
                                    ^^^^^^^^^^^^^^^^^^^^^^
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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