从显示的表中发送特定数据（PHP）

Question

I have complicated problem enter image description here

In this image I created php page to get the data from mysql database and every message have id in database If I click on image of check mark we will go to another page to answer the message

I get the id already from the DB

"SELECT msgId.....

and store it in var from the next array

while($row = mysqli_fetch_array($result)){
            ..............
            $msgIdVar = $row['msgId'];

and the check mark image is input form

<input type="image" src="img/chckMrk.jpg" alt="Submit Form" name="msgIdVar" value=""/>

when I try to pass the $row['msgId'] as a $_POST var, it didn't working with me!

<input type="image" src="img/chckMrk.jpg" alt="Submit Form" name="msgIdVar" value="' . <?php echo $msgIdVar; ?> . '"/>

also this doesn't work:

.....value="' . <?php echo $row['msgId']; ?> . '"/>

The problem here:

I want if we click the second message for example, send the id for this message to another page

How can i do it???

Answer 1

You can't use an <input type="image"> to send data using a form. Use an <input type="hidden">, and use your image as the trigger to submit the form:

<form method="post" action="">
    <input type="hidden" name="msgIdVar" value="<?php echo $msgIdVar ?>" />
    <input type="image" src="img/chckMrk.jpg" alt="Submit Form" onclick="this.form.submit()" />
</form>