PHP在特定页面的指定字符串后获得5个附加字符并列出它们

Question

Note: I have edited the post on 2017/08/20

I'm trying to obtain a list of product page's URL that goes "www.example.com/product/11111/".

There are over 200 different products available and each of them has its own product page, I want to print out each product in a PDF file.

On "www.example.com/productlist/", there are URLs that lead to each product's page.

So, what I'm trying to do is

1. Obtain URLs that I need from "www.example.com/productlist/"
2. Generate PDF files of URLs that I have obtained

Answer 1

Insufficient Information: You did not provide me with much information about the code you already have and how the website will get the 200 URLs, so I can't write the whole code because it depends on the way your website will get the links from.

If you explain more about how the website is supposed to get the links, I will help you put them into an array and save them into a file and implement the rest of the code!

1-) Thing I understood is getting the last 5 characters

As you just want the last 5 characters, not the whole last part, you can do something like this.

    $string = "http://example.com/folder/example/1234567"; //your link
    $characters = strlen($string);  //gets the characters count
    $letters = 5;  //edit 5 to show more or less manually
    $code = substr($string, $characters - $letters, $characters);

    echo $code; //will show the last 5 characters 

I am always here to help. Good luck!