如何在我的查询中包含<a href>所有URL出现内容[关闭]

Question

alright, i think the solution to my question is to use REGEX, but my current knowledge of it hinders me to achieve the result that i want.

so basically, how do i make all URL occurrence in my posts/text entries to wrap inside an <a href> element when being queried.

when i echo $content; from a database it will display as:

this is a link http://somerandomsite.com, check it out!

but how can i make the link inside a text to be contained in <a href> tag when displayed.

id be honest to say that i dont know how to properly write the syntax. but this is what ive come up with.

//get url from content
$link = strstr($content, 'http://');

//insert <a href> for all $link inside $content
//then display $content with all links wrapped in <href>

Answer 1

$a = 'this is a link http://somerandomsite.com, check it out!';

$a = preg_replace("/\b((?:http\:\/\/)|(?:www\.))([^ ,]+)/", "<a href=\"$1$2\">$1$2</a>", $a);

echo $a;