dpbe81245 2017-05-07 08:27
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MySQL:如何选择相同的值

I have a cell value in mysql table 85,77,25 datatype is VARCHAR. I'm targeting to select all having 85 identically, but I'm thinking if the 85 value increase to 185 or other number more than 185 that also contain 85, and I'm using LIKE operator in where clause. How can I properly select all of cell value having 85 only not 185, 285 and so on.

Example I have 4 rows and the value is

1. 20,85,77
2. 85,60,120
3. 10,4,85
4. 50,61,285

I need to get only those having '85' so the result should be from 1 to 3, I'm trying to combine LIKE operator beginning,ending and containing.

SELECT * from icweb.tbl_message 
where 
(to_id LIKE '%85' and to_id LIKE '85%' and to_id LIKE '%85%')
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1条回答 默认 最新

  • dongyizhuang0134 2017-05-07 08:37
    关注

    You can use this

    SELECT * from icweb.tbl_message  
    where 
    (to_id LIKE '%,85' OR to_id LIKE '85,%' OR to_id LIKE '%,85,%' OR to_id = '85')
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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