程序在php中输错了输出？

Question

this code is to sum up 1 to 10 using the arithmetic progression

The output should be as 550 code:

<?php
        $total = 0;
        for ($i = 1; $i <= 10; $i++) {
            for ($j = 10; $j >=1 ; $j++) {
                $total =  $i + $j;
                break;
            } 
        } 
        $total = $total / 2;
        print $total."<br/>";
?>

Current output: 10 Expected output: 550

and In second case I have

<?php
    $list = [1, 2, 3, 4];
    foreach ($list as $row) 
    {
        switch ($row) 
        {
            case 1:
                print "This is One
";
            case 2:
                print "This is Two
";
            case 3:
                print "This is Three
";
        }
    }
    print "

";
?>

Current output: This is One This is Two This is Three This is Two This is Three This is Three

Expected output: This is One This is Two This is Three This is Four

In my first code I want to get 550 through first program but when I run it throw wrong output i.e 122666133 and in case of second program current program throw wrong output but expected output as I mention above. So, How can I fix this issue ?Please help me.

Thank You

Answer 1

# Please check Below Code: 
    <?php
        $list = [1, 2, 3, 4];
        foreach ($list as $row) 
        {
            switch ($row) 
            {
                case 1:
                    print "This is One
";
                    break;
                case 2:
                    print "This is Two
";
                    break;
                case 3:
                    print "This is Three
";
                    break;
                default:
                    print "This is Four
";
                    break;
            }
        }
        print "

";
    ?>