2个回答

Class Guy { public bool PlaceBet(int BetAmount, int DogToWin) { if (Cash >= BetAmount) return true; else return false; } } //创建并实例化了一个guy类数组； private void button2_Click(object sender, EventArgs e) { for (int i = 0; i <= 2; i++) { if(guy[i].PlaceBet==true){ label1.Text="blablablah"; } } } 错误：==无法应用于方法组与bool型操作数，说placebet是一个方法组，怎么回事啊？那我怎么判断guy[i]的真假呢？

C语言判断真假问题，求解释
20.How manystatements are truefor xwhichisan integer? !x%2 !x%2!=0 !!(x%2==0) x%2&1 A. 0 B. 1 C. 2 D. 3

Problem Description Samuel only has the average data,Please use these figures to predicate ,if the total number reached or higher than the number is given,Samuel's hope will come true. Input The first line of the input is t,which represents the number of the test cases. Each of the test cases only contains 2 parts: The average data of a week p(the unit is million people), the expected year's number q(the unit is million people too).Notice a year has only 52 weeks. Output If the number is reached,output “Oh,Samuel's hope will come true,thanks to the DcSLs.” else output“Unfortunately,Samuel's hope will not come true,more tourists are welcomed!” Sample Input 3 3 151 2 105 4 208 Sample Output Oh,Samuel's hope will come true,thanks to the DcSLs. Unfortunately,Samuel's hope will not come true,more tourists are welcomed! Oh,Samuel's hope will come true,thanks to the DcSLs.

java怎么实现对合同上的公章鉴别真假

Problem Description A two-party system is a form of party system where two major political parties dominate voting in nearly all elections, at every level. As a result, all, or nearly all, elected offices end up being held by candidates endorsed by one of the two major parties.Under a two-party system, one of the two parties typically holds a plurality in the legislature , and is referred to as the majority party. The smaller party is referred to as the minority party. Two-party systems are most common in polities with plurality vote counting system to prevent the problem of two similar candidates "splitting" the same voters. There is a small country under a two-party system, the two parties are party A and party B. Every time when parliament convened, members of both parties will submit Their proposals. Some of the proposals will be raised by some members of the same party, but each person can submit only one. Of course, some people may object to certain proposals of the other party. If a member's proposal is adopted and all his objection cases are not adopted, then he will be pleased. As the country's president, you can arrange these proposals is adopted or not. You want to know , to make the numnber of people pleased with your decision maximum, which proposals must be adopted ? Input On the first line one positive number: the number of testcases. After that per testcase:One line with three integers a, b, n (0<=a,b<=100 and 0<=n<=200): the number of proposals by party A, by party B, and number of members of the parliament. The proposals are numbered from 1 to a+b, the first a are party A's, the latter b are party B's. n lines follow, each line represents a member of the parliament, begin with two integers ri,mi(1<=ri<=a+b, 0<=mi<a+b): the proposal submit by him, the number of proposals he object to. And then follows mi integers indicate the proposal he object to. Output For each test case, you should output 2 lines. The first line will contains one integer, the maxium number of people pleased. The second line begins with an integer x, indicates there are x proposals must be adopted. Then output the x proposals in ascending order of their id. There is a space between each two proposals. Sample Input 3 2 1 3 1 0 1 0 3 0 2 1 3 1 0 2 1 3 3 0 2 1 4 1 0 1 1 3 2 0 3 2 1 2 Sample Output 3 2 1 3 2 1 1 3 2 1 2
C#中含有or,and的字符中判断真假（即返回true/false）

#include是将包含文件内容展开到cpp文件中， 那假如我写一个头文件，里面写#include<stdio.h> 那么我写多个.h文件形成多重包含的结构，就是.h套.h套.h, 那么每一个头文件里面假如编译是不是就将所有的.h文件一层一层展开再拷贝到.h文件里。 这样是不是重复定义了好多个毫无意义的副本 另外， 大神有没有经典的数据结构源码推荐下， 简洁易懂的， 子函数只用返回值判断真假，不写printf（）的
ajax 做验证，返回真假
<p>这里是验证的代码 javascript 代码：</p> <pre name="code" class="js">if (z == "ajaxrepeat") { //ajax 验证是否重复 var url2 = y.attr("url"); //获取需要对比的输入框的ID var proving = \$.trim(x); if (proving != "") { \$.ajax({ url: url2, type: 'POST', data: { "paths": proving }, dataType: "html", success: function(data){ //拆分字符串 var data2 = data.split(","); if (data2[0] == "true") { if (data2[1] != undefined) { var data3 = decodeURIComponent(data2[1]); } //改变提示 y.next(".provinghtml").html(data3); y.next(".provinghtml").css("color", "#79A605"); return true; } else { //否则，如果第二个字符串不为空，则弹出提示 if (data2[1] != undefined) { var data3 = decodeURIComponent(data2[1]); } //改变提示 y.next(".provinghtml").html(data3); y.next(".provinghtml").css("color", "#FF0000"); return false; } } }) } else { //改变提示 y.next(".provinghtml").html("请输入正确信息"); y.next(".provinghtml").css("color", "#FF0000"); return false; }</pre> <p> </p> <p>   哪位可以帮我看看要怎么返回真假，就差这个功能没有实现了</p>

String字符串判断真假
String str = "true&true||(true||false&(true||false))"; 如何用程序判断字符串结果为真还是假？

https能否省掉hash过程，直接对整个证书进行CA私钥加密，能解密则为真，不能则未假？
https通过根证书公钥解密摘要信息，然后和证书信息做hash后的值做了对比，从而判断证书的真伪。这里为什么不能直接省掉做hash的过程，直接对整个证书内容进行CA私钥加密，如果客户端用根证书中的公钥能解密则证书是真的，当然这里的能解密不是严格意义上的能解密，而是解密后的格式和正常格式一致，就认为能解密。而不能解密则认为证书是假的。 我自己的猜测： 1.数字证书需要找到这个证书的颁发者来验证证书真假，意味着颁发者一定是不能加密传输的，所以造成证书一部分加密，一部分非加密。很不整齐，虽然现在也是一部分加密，一部分非加密，但是加密部分仅是摘要信息，除摘要信息外部分是没有加密的。 2.如果整个证书加密，那客户端解密时根本不确定这个证书是真还是假，相比较对hash解密而言，对整个证书解密效率肯定会差很多。 3.如果整个证书加密，意味者证书发送到客户端，客户端完全不发看到证书的任何信息，除证书的颁发者。对维护、问题定位造成很大困难。 4.如果证书恰巧被篡改，而且篡改完的用户名和用户公钥随便通过一个私钥加密后传给客户端，客户端此时拿着本地CA公钥解密恰好解密出一个和正常公钥用户信息格式一样的数据，会骗过所有认证。客户端误认为这个证书是真的。虽然这种情况发生后，客户端拿到的公钥一定是不正确的（因为被篡改的证书不是通过CA私钥加密的），但客户端依然会用这样的一个错误公钥加密信息传递数据。这样的数据即无法被服务器解析也无法被篡改者解析，直接造成了https不可用。

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