另一个eval（）受害者

Question

Some code uses eval() to execute code stored in an array like this:

// $oOwner is an object
$strId = "abc";
$strClass = "someClass";
$aParams = array('a' => 'atext', 'b' => 'btext');

$this->menu = array(
"Entry 1" => ' openForm(\$oOwner,\$strId,\$strClass,\$aParams); ',
// ...
);

The values of the array's keys will be given directly into an eval() function.

Now I get an error: Parse error: syntax error, unexpected T_VARIABLE, expecting T_STRING ... eval()'d code on line 1

What is the problem?

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EDIT:

Loop through the array and eval() the values:

eval( $this->menu[$param[0]] );

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EDIT 2:

Now: "Entry 1" => " openForm(\$this->owner,\$strId,\$strClass,\$aParams); "

Using double quotes "..." leads to PHP Notice: Undefined variable: strId in ... : eval()'d code on line 1. Also for the other variables.

`

Answer 1

The way I tried always led to errors and I came up with the idea of putting the array in there as a string via var_export().

There are 2 attempts posted here: Store array in a string to eval() later