PHP创建一个空数组

Question

$number_array = array();

//in a while loop

//part of code
if(array_key_exists($read_num, $number_array))
{
        $arr[$read_num][A] .= $new_A;
}
else
{
$inner_arr = array( "$read_num" => array( "id"=>$read_num, "A"=>$new_A ) );
$number_array = array_push($number_array,$inner_arr);

unset($inner_arr);
}

I get error like:

Warning: array_key_exists() [function.array-key-exists]: The second argument should be either an array or an object in try.php on line 24
Warning: array_push() [function.array-push]: First argument should be an array in try.php on line 33

I declare an empty array outside of the while loop

$number_array = array();

what did i do wrong here that cause the error to appear

EDIT:

I have this value when I did the code above

Array
(
[0] => Array
    (
        [0011] => Array
            (
                [id] => 0011
                [A] => 2.50
                [B] => 2.00
                [C] => 5.40
            )

    )

[1] => Array
    (
        [0017] => Array
            (
                [id] => 0017
                [A] => 5.00
                [B] => 0.00
                [C] => 8.00
            )

    )

[2] => Array
    (
        [0022] => Array
            (
                [id] => 0022
                [A] => 1.00
                [B] => 0.00
                [C] => 1.60
            )

    )

How do I remove the [0] , [1] and [2] and make it as [0011] , [0017], [0022] so my array key exists can work

Answer 1

It's because you re-assign the return value of array_push to $number_array

$number_array = array_push($number_array,$inner_arr);

remove it :

array_push($number_array,$inner_arr);

Because array_push return new number of elements in the array not the array itself.

Alternatively you can just write:

$number_array[] = $inner_arr;

It's the same thing.