I need to display certain content on the document when the URL contains that particular content's ID. Currently, the USER will go through a series of steps for a security check. At the end, a cookie will be placed on their system to avoid doing the security check in 30 days. Now, let's say that the cookie fails to go on the system or it fails to locate the cookie on the user's system, there has to be a notice so the user doesn't get confused on why they are getting another security check before 30 days. So far, this is what I got:
Places the cookie on the computer (setcookie.php):
<?php
$cookie_name = "securitycheck";
$cookie_value = "29610741351979104njnj23j52nx72d72n892ccr3179hd3";
setcookie($cookie_name, $cookie_value, time() + (86400 * 30), "/"); // 86400 = 1 day
?>
Validates cookie (checkcookievalidation.php):
<head>
<?php
$cookie_name = "securitycheck";
?>
</head>
<body>
<?php
if(!isset($_COOKIE[$cookie_name])) {
echo "Cookie named '" . $cookie_name . "' is not set! Internal Error!";
header( 'Location: checkfinished.php?nocookieset' ) ;
} else {
echo "Cookie '" . $cookie_name . "' is set!<br>";
header("Location: checkfinished.php");
}
?>
</body>
Finished page (checkfinished.php) [This is where I'm stuck on]:
<div id="nocookieset" style="visibility: visible;" align="center"><h3>Although the check did complete with errors. We were unable to set the cookie due to an internal server error. Please contact the web team about this if the issue continues.</h3></div>
- Now I need it to show the Div with the nocookieset id if the URL contains the id in there (such as http://example.com/example.php?nocookieset)
If it doesn't contain ?nocookieset in the URL, then it won't show the Div.
How can I make this happen?
