dongying3830 2013-03-08 13:43
浏览 44
已采纳

递归PHP函数未返回预期值

I am trying to create a function that will create a unique username for each user stored in the database.

My plan was to create a username by concatenating the first and last name then check if this username was taken. If it wasn't just store it in the database and if it was then add a number on the end of it.

For example if ConnorAtherton was taken the function would next check ConnorAtherton1, ConnorAtherton2 until it found a unique username.

Here is the function (I have added some echo statements for debugging)

    function createUserName($username, $counter){

        global $fname, $lname;

        echo "\t\t\tUsername at Start - " . $username . "
";

        // connect to database
        require($_SERVER['DOCUMENT_ROOT'] . "/inc/db.connect.php");

        $stmt = $conn->prepare('SELECT * FROM users WHERE username = ?');
        $stmt->bind_param('s', $username); 
        $stmt->execute();
        $stmt->store_result();

        echo "\t\t\tUsername before loop - " . $username . "
";

            if( $stmt->num_rows > 0){

                //construct original name and try again
                $username = ucfirst($fname) . ucfirst($lname) . $counter;
                $counter++;
                createUserName($username, $counter);

            }

            echo "\t\t\tUsername after loop - " . $username . "

";

            return $username;
    }

Here is what it returns to the console

    Username at Start - ConnorAtherton
    Username before loop - ConnorAtherton
    Username at Start - ConnorAtherton1
    Username before loop - ConnorAtherton1
    Username at Start - ConnorAtherton2
    Username before loop - ConnorAtherton2
    Username after loop - ConnorAtherton2

    Username after loop - ConnorAtherton1

It returns the correct value after the loop (ConnorAtherton2) to begin with but I don't know why there would be a second value after the loop.

It returns ConnorAtherton1 and I need it to return ConnorAtherton2.

Any help is greatly appreciated.

  • 写回答

2条回答 默认 最新

  • doutian3269 2013-03-08 13:47
    关注

    The code executes as expected. What you are seeing is just the stack unwinding from the recursive calls.

    You should modify your function to exit after the recursive call, by returning the result from the recursive call

         //...
        $counter++;
        return createUserName($username, $counter);
     }
     //... Rest of fn omitted
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(1条)

报告相同问题?

悬赏问题

  • ¥15 metadata提取的PDF元数据,如何转换为一个Excel
  • ¥15 关于arduino编程toCharArray()函数的使用
  • ¥100 vc++混合CEF采用CLR方式编译报错
  • ¥15 coze 的插件输入飞书多维表格 app_token 后一直显示错误,如何解决?
  • ¥15 vite+vue3+plyr播放本地public文件夹下视频无法加载
  • ¥15 c#逐行读取txt文本,但是每一行里面数据之间空格数量不同
  • ¥50 如何openEuler 22.03上安装配置drbd
  • ¥20 ING91680C BLE5.3 芯片怎么实现串口收发数据
  • ¥15 无线连接树莓派,无法执行update,如何解决?(相关搜索:软件下载)
  • ¥15 Windows11, backspace, enter, space键失灵