如何在PHP中以特定格式显示今天的下3个日期？

Question

I am trying to print out the next 3 days from today. This code works fine but I need the dates to be in this format "2018 Sept, 29". Changing format keeps giving me errors.

<?php
// Set timezone
date_default_timezone_set('AFRICA/LAGOS');

// Start date
$date = date('Y-m-d');
// End date
$end_date = date('Y-m-d', strtotime("+3 days"));

while (strtotime($date) <= strtotime($end_date)) {
    $date=DateTime::createFromFormat('Y-m-d', $date)->modify('+1 day')->format('Y-m-d');
    echo $date.', ';
}
echo "<br><br>";
?>

Answer 1

You can easily do it with date() and for() loop:-

<?php

date_default_timezone_set('AFRICA/LAGOS');

$date = date('Y-m-d');
for($i =1;$i<=3;$i++){
  echo $end_date = date('Y M,d', strtotime("+$i days"));
  echo PHP_EOL;
}

https://3v4l.org/YXZEe

A bit functional approach:

<?php

function getNextDatesFromCurrentDate($how_many_dates){
    date_default_timezone_set('AFRICA/LAGOS');

    for($i =1;$i<=$how_many_dates;$i++){
        echo $end_date = date('Y M,d', strtotime("+$i days"));
        echo PHP_EOL;
    }
}

getNextDatesFromCurrentDate(3);

https://3v4l.org/1vKVA