duanqianwei2485 2011-08-04 17:13
浏览 101
已采纳

通过ANT获取和使用父目录

I have a directory structure & build.xml like this

    /path-to-project/src/prj1
    /path-to-project/src/prj2

    /path-to-project/tests
    /path-to-project/tests/build.xml

I have to somehow get the path

    /path-to-project/

in my build.xml

My build.xml is like this

<project name="php-project-1" default="build" basedir=".">
  <property name="source" value="src"/>
    <target name="phploc" description="Generate phploc.csv">
      <exec executable="phploc">
        <arg value="--log-csv" />
        <arg value="${basedir}/build/logs/phploc.csv" />
        <arg path="${source}" />
      </exec>
    </target>
</project>

Here I somehow want to get value of ${source} as /path-to-project/src/ but I am not getting it with ${parent.dir}

Is it possible to get this path in the build.xml?

  • 写回答

2条回答 默认 最新

  • donglei_0507 2011-08-04 17:22
    关注

    You can use .. just as you do on the command-line to navigate to the parent directory.

    <project name="php-project-1" default="build" basedir=".">
      <property name="root.dir" location=".."/>
      <property name="source" location="${root.dir}/src"/>
      ...
    </project>
    

    Update: Changed value to location as per martin's answer which you should accept.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(1条)

报告相同问题?

悬赏问题

  • ¥50 永磁型步进电机PID算法
  • ¥15 sqlite 附加(attach database)加密数据库时,返回26是什么原因呢?
  • ¥88 找成都本地经验丰富懂小程序开发的技术大咖
  • ¥15 如何处理复杂数据表格的除法运算
  • ¥15 如何用stc8h1k08的片子做485数据透传的功能?(关键词-串口)
  • ¥15 有兄弟姐妹会用word插图功能制作类似citespace的图片吗?
  • ¥200 uniapp长期运行卡死问题解决
  • ¥15 latex怎么处理论文引理引用参考文献
  • ¥15 请教:如何用postman调用本地虚拟机区块链接上的合约?
  • ¥15 为什么使用javacv转封装rtsp为rtmp时出现如下问题:[h264 @ 000000004faf7500]no frame?