如何获取给定json的值并获得结果

Question

I am trying to get the result for the below query

$users = DB::select("SELECT FIND_IN_SET('l','a,b,c,d') as Res");

and while i do

return $users;

Here is my json

[{"Res":0}]

When i try to decode it, it shows me the error

json_decode() expects parameter 1 to be string, array given

When i var_dump i am getting as

array(1) { [0]=> object(stdClass)#773 (1) { ["Res"]=> int(0) } }

So, How can i get the result of the 'Res' ?

Answer 1

The solution is in the error:

json_decode() expects parameter 1 to be string, **array given**

That is, the result data is being returned as an array which based on your var_dump also contains your result object and subsequent data.

This should do it:

<?php
     $data = $users[0]->Res
     $decoded = json_decode($data);

Note that this is essentially just turning your JSON string into an object. You can use the second parameter to have it returned as an array if preferred:

<?php 
     $data = $users[0]->Res
     $decoded = json_decode($data, true);