dtbhp60824 2017-01-06 03:20
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Golang中的接口和整数比较

I don't understand why the first result is false while second is true.

Any help will be appreciated.

func main() {
    var i interface{}

    i = uint64(0)
    fmt.Println("[1] ", reflect.TypeOf(i), i == 0)

    i = 0
    fmt.Println("[2] ", reflect.TypeOf(i), i == 0)

    var n uint64 = 32
    fmt.Println("[3] ", reflect.TypeOf(n), n == 32) 
}

// result
// [1]  uint64 false
// [2]  int true
// [3]  uint64 true

Try it here Go playground

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1条回答 默认 最新

  • douxiongzhen2126 2017-01-06 03:47
    关注

    Because 0 is an untyped constant whose default type is int, not uint64, and when doing comparison with an interface, the thing you are comparing to must be both the same type and the same value for them to be considered equal.

    https://golang.org/ref/spec#Comparison_operators

    The equality operators == and != apply to operands that are comparable. The ordering operators <, <=, >, and >= apply to operands that are ordered. These terms and the result of the comparisons are defined as follows:

    A value x of non-interface type X and a value t of interface type T are comparable when values of type X are comparable and X implements T. They are equal if t's dynamic type is identical to X and t's dynamic value is equal to x.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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