dtbhp60824
2017-01-06 03:20 阅读 109
已采纳

Golang中的接口和整数比较

I don't understand why the first result is false while second is true.

Any help will be appreciated.

func main() {
    var i interface{}

    i = uint64(0)
    fmt.Println("[1] ", reflect.TypeOf(i), i == 0)

    i = 0
    fmt.Println("[2] ", reflect.TypeOf(i), i == 0)

    var n uint64 = 32
    fmt.Println("[3] ", reflect.TypeOf(n), n == 32) 
}

// result
// [1]  uint64 false
// [2]  int true
// [3]  uint64 true

Try it here Go playground

  • 点赞
  • 写回答
  • 关注问题
  • 收藏
  • 复制链接分享

1条回答 默认 最新

  • 已采纳
    douxiongzhen2126 douxiongzhen2126 2017-01-06 03:47

    Because 0 is an untyped constant whose default type is int, not uint64, and when doing comparison with an interface, the thing you are comparing to must be both the same type and the same value for them to be considered equal.

    https://golang.org/ref/spec#Comparison_operators

    The equality operators == and != apply to operands that are comparable. The ordering operators <, <=, >, and >= apply to operands that are ordered. These terms and the result of the comparisons are defined as follows:

    A value x of non-interface type X and a value t of interface type T are comparable when values of type X are comparable and X implements T. They are equal if t's dynamic type is identical to X and t's dynamic value is equal to x.

    点赞 评论 复制链接分享

相关推荐