按频率图对字符串片段进行排序

Question

I have a slice of slices of strings, and want to sort them by their frequency, I tried to follow the byAge example from the docs here http://golang.org/pkg/sort/ but was unable how to pass a list of frequencies to it.

Meaning, the outcome of the example would be:

 [[a,b] [a,b,c,d] [a,c,d,e]]

Would the approach be to have "a" be represented by a custom struct with frequency as it's own attribute? That seems to be more in line with the byAge example.

func main() {

    transactions := [][]string{{"a", "b"}, {"b", "c", "d", "a"}, {"c", "d", "e", "a"}}

    frequencies := map[string]int{
        "a": 3,
        "b": 2,
        "c": 2,
        "d": 2,
        "e": 1,
    }

    fmt.Println(transactions, frequencies)

}

Answer 1

In case you need more than the data you want to sort in the sorting process, a common way is to implement your own struct, yes. In your case this would be something like this (on play):

type SortableTransaction struct {
    data        []string
    frequencies map[string]int
}

data would be the slice with strings and frequencies your specific frequency table.

The following implementation could be used for the Sort interface:

func (s SortableTransaction) Len() int { return len(s.data) }
func (s SortableTransaction) Less(i, j int) bool {
    return s.frequencies[s.data[i]] > s.frequencies[s.data[j]]
}
func (s SortableTransaction) Swap(i, j int) {
    s.data[j], s.data[i] = s.data[i], s.data[j]
}

If your frequency table is constant, you can declare it at package level of course.

In case you want to sort the outer slice as well, you'd have to sort the inner slices first and then the outer slices.