drh78568 2019-08-01 12:50
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I am trying to replace a specific position character from an array of strings. Here is what my code looks like:

package main

import (

func main() {
    str := []string{"test","testing"}
    str[0][2] = 'y'

Now, running this gives me the error:

cannot assign to str[0][2]

Any idea how to do this? I have tried using strings.Replace, but AFAIK it will replace all the occurrence of the given character, while I want to replace that specific character. Any help is appreciated. TIA.

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  • dongzhansong5785 2019-08-01 12:55

    Strings in Go are immutable, you can't change their content. To change the value of a string variable, you have to assign a new string value.

    An easy way is to first convert the string to a byte or rune slice, do the change and convert back:

    s := []byte(str[0])
    s[2] = 'y'
    str[0] = string(s)

    This will output (try it on the Go Playground):

    [teyt testing]

    Note: I converted the string to byte slice, because this is what happens when you index a string: it indexes its bytes. A string stores the UTF-8 byte sequence of the text, which may not necessarily map bytes to characters one-to-one.

    If you need to replace the 2nd character, use []rune instead:

    s := []rune(str[0])
    s[2] = 'y'
    str[0] = string(s)

    In this example it doesn't matter though, but in general it may.

    Also note that strings.Replace() does not (necessarily) replace all occurrences:

    func Replace(s, old, new string, n int) string

    The parameter n tells how many replacement are to be performed max. So the following also works (try it on the Go Playground):

    str[0] = strings.Replace(str[0], "s", "y", 1)

    Yet another solution could be to slice the string up until the replacable character, and starting from the character after the replacable one, and just concatenate them (try this one on the Go Playground):

    str[0] = str[0][:2] + "y" + str[0][3:]

    Care must be taken here too: the slice indices are byte indices, not character (rune) indices.

    See related question: Immutable string and pointer address

    本回答被题主选为最佳回答 , 对您是否有帮助呢?



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