drh78568
2019-08-01 12:50
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已采纳

在golang中替换字符串中的字符

I am trying to replace a specific position character from an array of strings. Here is what my code looks like:

package main

import (
    "fmt"
)

func main() {
    str := []string{"test","testing"}
    str[0][2] = 'y'
    fmt.Println(str)
}

Now, running this gives me the error:

cannot assign to str[0][2]

Any idea how to do this? I have tried using strings.Replace, but AFAIK it will replace all the occurrence of the given character, while I want to replace that specific character. Any help is appreciated. TIA.

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我正在尝试从字符串数组中替换特定的位置字符。 这是我的代码:

  package main 
 
import(
“ fmt” 
)
 
func main(){
 str:=  [] string {“ test”,“ testing”} 
 str [0] [2] ='y'
 fmt.Println(str)
} 
   
 
  

现在,运行此命令给我错误:

 无法分配给str [0] [2] 
   
 
  

任何想法该怎么做? 我试过使用strings.Replace,但AFAIK将替换所有出现的给定字符,而我想替换该特定字符。 任何帮助表示赞赏。 TIA。

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2条回答 默认 最新

  • dongzhansong5785 2019-08-01 12:55
    已采纳

    Strings in Go are immutable, you can't change their content. To change the value of a string variable, you have to assign a new string value.

    An easy way is to first convert the string to a byte or rune slice, do the change and convert back:

    s := []byte(str[0])
    s[2] = 'y'
    str[0] = string(s)
    fmt.Println(str)
    

    This will output (try it on the Go Playground):

    [teyt testing]
    

    Note: I converted the string to byte slice, because this is what happens when you index a string: it indexes its bytes. A string stores the UTF-8 byte sequence of the text, which may not necessarily map bytes to characters one-to-one.

    If you need to replace the 2nd character, use []rune instead:

    s := []rune(str[0])
    s[2] = 'y'
    str[0] = string(s)
    fmt.Println(str)
    

    In this example it doesn't matter though, but in general it may.

    Also note that strings.Replace() does not (necessarily) replace all occurrences:

    func Replace(s, old, new string, n int) string
    

    The parameter n tells how many replacement are to be performed max. So the following also works (try it on the Go Playground):

    str[0] = strings.Replace(str[0], "s", "y", 1)
    

    Yet another solution could be to slice the string up until the replacable character, and starting from the character after the replacable one, and just concatenate them (try this one on the Go Playground):

    str[0] = str[0][:2] + "y" + str[0][3:]
    

    Care must be taken here too: the slice indices are byte indices, not character (rune) indices.

    See related question: Immutable string and pointer address

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  • dongqian3198 2019-08-01 13:11

    Here's a function that will do that for you. It takes care of converting the string that you want to modify into a []rune, and then back out to string.

    If your intention is to replace bytes rather than runes, you can:

    • copy this function's code, rename it from runeSub to byteSub
    • change the r rune parameter to b byte

    Also available on repl.it

    package main
    
    import "fmt"
    
    // runeSub - given an array of strings (ss), replace the
    // (ri)th rune (character) in the (si)th string
    // of (ss), with the rune (r)
    //
    // ss - the array of strings
    // si - the index of the string in ss that you want to modify
    // ri - the index of the rune in ss[si] that you want to replace
    // r - the rune you want to insert
    //
    // NOTE: this function has no panic protection from things like
    // out-of-bound index values
    func runeSub(ss []string, si, ri int, r rune) {
      rr := []rune(ss[si])
      rr[ri] = r
      ss[si] = string(rr)
    }
    
    func main() {
      ss := []string{"test","testing"}
      runeSub(ss, 0, 2, 'y')
      fmt.Println(ss)
    }
    
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