drh78568 2019-08-01 12:50
浏览 2317
已采纳

在golang中替换字符串中的字符

I am trying to replace a specific position character from an array of strings. Here is what my code looks like:

package main

import (
    "fmt"
)

func main() {
    str := []string{"test","testing"}
    str[0][2] = 'y'
    fmt.Println(str)
}

Now, running this gives me the error:

cannot assign to str[0][2]

Any idea how to do this? I have tried using strings.Replace, but AFAIK it will replace all the occurrence of the given character, while I want to replace that specific character. Any help is appreciated. TIA.

  • 写回答

2条回答 默认 最新

  • dongzhansong5785 2019-08-01 12:55
    关注

    Strings in Go are immutable, you can't change their content. To change the value of a string variable, you have to assign a new string value.

    An easy way is to first convert the string to a byte or rune slice, do the change and convert back:

    s := []byte(str[0])
    s[2] = 'y'
    str[0] = string(s)
    fmt.Println(str)
    

    This will output (try it on the Go Playground):

    [teyt testing]
    

    Note: I converted the string to byte slice, because this is what happens when you index a string: it indexes its bytes. A string stores the UTF-8 byte sequence of the text, which may not necessarily map bytes to characters one-to-one.

    If you need to replace the 2nd character, use []rune instead:

    s := []rune(str[0])
    s[2] = 'y'
    str[0] = string(s)
    fmt.Println(str)
    

    In this example it doesn't matter though, but in general it may.

    Also note that strings.Replace() does not (necessarily) replace all occurrences:

    func Replace(s, old, new string, n int) string
    

    The parameter n tells how many replacement are to be performed max. So the following also works (try it on the Go Playground):

    str[0] = strings.Replace(str[0], "s", "y", 1)
    

    Yet another solution could be to slice the string up until the replacable character, and starting from the character after the replacable one, and just concatenate them (try this one on the Go Playground):

    str[0] = str[0][:2] + "y" + str[0][3:]
    

    Care must be taken here too: the slice indices are byte indices, not character (rune) indices.

    See related question: Immutable string and pointer address

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(1条)

报告相同问题?

悬赏问题

  • ¥15 FLUENT如何实现在堆积颗粒的上表面加载高斯热源
  • ¥30 截图中的mathematics程序转换成matlab
  • ¥15 动力学代码报错,维度不匹配
  • ¥15 Power query添加列问题
  • ¥50 Kubernetes&Fission&Eleasticsearch
  • ¥15 報錯:Person is not mapped,如何解決?
  • ¥15 c++头文件不能识别CDialog
  • ¥15 Excel发现不可读取的内容
  • ¥15 关于#stm32#的问题:CANOpen的PDO同步传输问题
  • ¥20 yolov5自定义Prune报错,如何解决?