dqrzot2791
2016-06-07 20:13
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Golang:如何从字符串中替换第n个字符

I want to replace nth char from in the original string, I can access nth char from string by using chars[i], but when I assign value to chars[i] it giving error.

package main
import "fmt"

func main() {
  var chars = "abcdef"
  fmt.Println(string(chars[3]))
  chars[3] = "z" // is not working, 
}

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我要替换原始字符串中的第n个字符,我可以使用chars [i]访问字符串中的第n个字符 ],但是当我将值赋给chars [i]时会出错。

 包main 
import“ fmt” 
 
func main(){
 var chars =“ abcdef” 
 fmt.Println(string(chars [3])  )
 chars [3] =“ z” //不起作用,
} 
   
 
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3条回答 默认 最新

  • doupinge9055 2016-06-07 20:22
    已采纳

    This is happening because chars is actually a string and is immutable. If you declared it appropriately (as a byte slice) then you can assign to it as you're attempting. Here's an example;

    package main
    import "fmt"
    
    func main() {
      var chars = []byte{'a', 'b', 'c', 'd', 'e', 'f'}
      fmt.Println(string(chars[3]))
      fmt.Printf("%T
    ", chars)
      chars[3] = 'z'
      fmt.Println(string(chars))
    }
    

    https://play.golang.org/p/N1sSsfIBQY

    Alternately you could use reslicing as demonstrated in the other answer.

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  • duanhuang4841 2016-06-07 20:20

    Strings are immutable.

    chars = chars[:3] + "z" + chars[4:]
    
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  • doubo1883 2016-06-07 20:34

    Use slice indexing to remove the character at the index, and place a new character there instead.

    package main
    import "fmt"
    
    func main() {
      var chars = "abcdef"
      fmt.Println(string(chars[3]))
      chars = chars[:3] + "z" + chars[3+1:]
      fmt.Println(string(chars[3]))
    }
    

    Output:

    d
    z
    

    [:3] selects everything in the slice from the beginning up until the index 3, and [3+1:] selects everything from the index (3+1) until the end of the slice. Put the character you wanted in-between the two statements and cat them all together for the effect of replacing a character at a specific index.

    If you want to replace a specific character (i.e. all (or some of) the instances of the letter 'b') you can use the strings.Replace function.

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