golang将os.ModePerm转换为字符串

Question

I would like to have as a string the permissions representation of a file. Here is what I want to do :

fileInfo, err := os.Lstat(path)
fileMode := fileInfo.Mode()
// fileMode.String() gives dturwxrwxrwx or -rwxrwxrwx
// which i do not want because the size is not always the same
unixPerms := fileMode & os.ModePerm

I get -rwxrwxrwx for both cases, which is close to what i am looking for.

However, the returned object is of type os.FileMode. How can I then convert it into a string?

Answer 1

You can pass either one of your variables, type (os.FileMode), as an argument to the Sprintf method from the fmt package.

Leveraging this method will convert your type into a string, which can then be used as a string throughout the remainder of your program.

Example usage below:

package main

import (
    "fmt"
    "os"
)

func main() {
    fileInfo, err := os.Lstat(path)
    if err != nil {
        // catch err
    }
    fileMode := fileInfo.Mode()
    // fileMode.String() gives dturwxrwxrwx or -rwxrwxrwx
    // which i do not want because the size is not always the same
    unixPerms := fileMode & os.ModePerm

    permString := fmt.Sprintf("%v", unixPerms)
    fmt.Println(permString)
}