Golang中的正则表达式：如何设置使字符串不匹配的字符？

Question

I am a noob about regular expressions (sorry). I was trying to make a very simple markup language that matches bold and italic and then converts them to HTML. Here is an example for bold that I'm using:

var bold = regexp.MustCompile("\\*([^\\*]+)\\*")

It matches everything between two asterisks. Now, I'd like it to match *test* but not \*test*. Since I don't know much about regular expressions but I'm trying to make this experiment, I'd like to know what's the way for that. I searched everywhere but couldn't find the way to make this work.

Answer 1

Updated

Go does not support lookbehinds. So a workaround can be:

(?:\A|(?:[^\\]+|\A)(\\{2})+|[^\\])\*([^\\*]+)\*