duanri1985 2018-06-11 16:19
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从函数返回空接口的切片

Can someone explain why this doesn't work and how can we return slices of interfaces, []interface{}, from functions like showed in the example?

import (
    "fmt"
)

func main() {
    var test []string
    Test(&test)
    fmt.Println(test)
}

func Test(t interface{}) {
    a := []interface{}{"first", "second"}
    fmt.Println(a)
    t = a
}

Example of running code can be found here: https://play.golang.org/p/vcEGHSdWrjv

BTW, this is the func I'm trying to extract data from: https://godoc.org/github.com/mongodb/mongo-go-driver/mongo#Collection.Distinct

Note: the type we expect is not always of type []string, I'm just using string as an example here.

Thanks!

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  • doubi1818 2018-06-11 18:06
    关注

    Because an []string and a []interface{} are different types, you cannot assign one to the other.

    You must copy the slice to convert []interface{} to a slice of some specific type. If you know that the []interface{} always contains string values, then use the following:

    func stringSlice() []string {
        a := []interface{}{"first", "second"} // query result
        fmt.Println(a)
    
        result := make([]string, len(a))
        for i := range a {
           var ok bool
           result[i], ok = a[i].(string)
           if !ok {
              // handle error with unexpected type
           }
        }
        return result
    }
    

    If the result can have arbitrary element types, then use reflection to copy the slice:

    func anySlice(result interface{}) {
        a := []interface{}{"first", "second"} // query result
    
        slice := reflect.ValueOf(result).Elem()
        elementType := slice.Type().Elem()
        for _, v := range a {
            rv := reflect.ValueOf(v)
            if !rv.Type().AssignableTo(elementType) {
                // handle error with unexpected type
            }
            slice.Set(reflect.Append(slice, rv))
        }
    }
    

    Use it like this:

    var s []string
    anySlice(&s)
    

    playground example

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