golang crontab每天午夜执行函数

Question

I want to execute function using this crontab library https://github.com/robfig/cron every day at 12:05PM. This is my current code :

cronHandler.AddFunc("@midnight", func() {
fmt.Println("crontab ping")
}

How i can execute my function using crontab every day at 03:00AM, time zone +2 ? My problem is current function use timezone of my server, and second problem this library not allow to specific specific hour when execute. How i can do this ?

Answer 1

This can be done with the cron library along with a few minor adjustments to your code.

A few things:

1. Locate your timezone of choice by finding it within a list from the timezone database, i.e. here
2. Load this timezone into the time.LoadLocation or utilize the time.FixedZone method if the .LoadLocation method does not work for you, see the time docs for more info on the methods available
3. Initialize a new instance of the Cron job runner using the custom location method NewWithLocation, see docs here
4. Edit your first argument to .AddFunc method in order to add a more granular cron schedule, replacing the generic @midnight with a more specific 0 5 * * * * representing every day @ 12:05AM or replace with whatever your desired cron execution time is at the new, custom location

Full example below:

// pass in your specific zone name, using USA/LA as example
customLocation := time.LoadLocation("America/Los_Angeles")

// initialize new cron job runner with custom location
cronHandler := cron.NewWithLocation(customLocation)

// the 0/24th hour and 5th minute of every day
cronHandler.AddFunc("0 5 * * * *", func() {
    fmt.Println("crontab ping")
})