如何在结构文字中将布尔指针设置为true？

Question

I have the function below which accepts a bool pointer. I'm wondering if there is any notation which allows me to set the value of the is field to true in the struct literal; basically without to define a new identifier (i.e. var x := true ; handler{is: &x} )

package main

import "fmt"

func main() {
    fmt.Println("Hello, playground")
    check(handler{is: new(bool) })
}


type handler struct{
    is *bool
}

func check(is handler){}

Answer 1

You can do that but it's not optimal:

h := handler{is: &[]bool{true}[0]}
fmt.Println(*h.is) // Prints true

Basically it creates a slice with one bool of value true, indexes its first element and takes its address. No new variable is created, but there is a lot of boilerplate (and backing array will remain in memory until the address to its first element exists).

A better solution would be to write a helper function:

func newTrue() *bool {
    b := true
    return &b
}

And using it:

h := handler{is: newTrue()}
fmt.Println(*h.is) // Prints true

You can also do it with a one-liner anonymous function:

h := handler{is: func() *bool { b := true; return &b }()}
fmt.Println(*h.is) // Prints true

Or a variant:

h := handler{is: func(b bool) *bool { return &b }(true)}

To see all your options, check out my other answer: How do I do a literal *int64 in Go?