数组合并排序（使用指针和函数）

Question

数组合并。用户输入两个有序（从小到大）的数组，合并后仍然成为一个有序（从小到大）数组输出。（要求使用函数和指针作为参数传递完成）
自己写的运行结果不对，dalao帮忙改改错

#include<stdio.h>
void hb(int a[], int b[], int c[]);
int main()
{
int a[5] = { 0 }, b[5] = { 0 };
int c[10] = { 0 };
int* pi = a, * pj = b, * pk = c;
printf("请输入数组a\n");
for (pi =a; pi < a+5; pi++)
scanf_s("%d", pi);
printf("请输入数组b\n");
for (pj =b; pj <b+5; pj++)
scanf_s("%d", pj);
hb(a, b,c);
for (pk = c; pk < c + 10; pk++);
{
printf("%d ", *pk);
}
}
void hb(int a[], int b[],int c[])
{
int* pa, * pb, * pc;
pa = a, pb = b, pc = c;
for (;(pa<a+5)&&(pb<b+5);pa++,pb++)
{
if (*pa> *pb) {
pc = pb, pc++;
pc = pa, pc++;
}
else {
pc = pa, pc++;
pc = pb, pc++;
}
}
}

Answer 1

我这个运行过了的，你对比下，你的程序有3点问题，其中前面的已经说了一个就是要用星号代表对值做改变，但是
要认识到，你逻辑是排序，而不是直接交叉；第三个问题，你输出c数组那个for循环有冒号，后面输不出了

#include <stdio.h>
void hb(int a[], int b[], int c[]);
int main()
{
    int a[5] = { 0 }, b[5] = { 0 };
    int c[10] = { 0 };
    int* pi = a, * pj = b, * pk = c;
    printf("请输入数组a\n");
    for (pi = a; pi < a + 5; pi++)
        scanf_s("%d", pi);
    printf("请输入数组b\n");
    for (pj = b; pj < b + 5; pj++)
        scanf_s("%d", pj);
    hb(a, b, c);
    for (pk = c; pk < c + 10; pk++)
    {
        printf("%d ", *pk);
    }
}
void hb(int a[], int b[], int c[])
{
    int* pa, * pb, * pc;
    pa = a, pb = b, pc = c;
    for (; (pa < a + 5) && (pb < b + 5);)
    {
        if (*pa > * pb)
        {
            *pc = *pb, pb++; pc++;
        }
        else
        {
            *pc = *pa, pa++; pc++;
        }
    }
    while (pa < a + 5) {
        *pc = *pa, pa++; pc++;
    }
    while (pb < b + 5) {
        *pc = *pb, pb++; pc++;
    }
}