matlab解方程 如下所示

Question

背景：已知 b c 求解a的值

%解方程开始%

clc

clear all

syms a b c X;

eq1=tan(a)*tan(a)-tan(a+b)*tan(a+b)-c==0;

X=solve(eq1,a,'ReturnConditions',true)

%解方程结束%

X =

包含以下字段的 struct:

         a: [1×1 sym]

parameters: [1×2 sym]

conditions: [1×1 sym]

请问如何把X的值显示出来，现在我这边无法使用

Answer 1

clc

clear all

syms a b c X;

eq1=tan(a)*tan(a)-tan(a+b)*tan(a+b)-c==0;

[solx, params, conds] = solve(eq1, a, 'ReturnConditions', true)

输出：

 
solx =
 
atan(z1) + pi*k
 
 
params =
 
[ k, z1]
 
 
conds =
 
tan(b) ~= 0 & c + 2*z1^3*tan(b) + tan(b)^2 + 2*z1*tan(b) + c*z1^2*tan(b)^2 ~= z1^4*tan(b)^2 + 2*c*z1*tan(b) & ~in((atan(z1) - atan(1/tan(b)) + pi*k)/pi, 'integer') & in(k, 'integer') & (z1 == root(z^4*tan(b)^2 - 2*z^3*tan(b) - c*z^2*tan(b)^2 + 2*c*z*tan(b) - 2*z*tan(b) - c - tan(b)^2, z, 1) | z1 == root(z^4*tan(b)^2 - 2*z^3*tan(b) - c*z^2*tan(b)^2 + 2*c*z*tan(b) - 2*z*tan(b) - c - tan(b)^2, z, 2) | z1 == root(z^4*tan(b)^2 - 2*z^3*tan(b) - c*z^2*tan(b)^2 + 2*c*z*tan(b) - 2*z*tan(b) - c - tan(b)^2, z, 3) | z1 == root(z^4*tan(b)^2 - 2*z^3*tan(b) - c*z^2*tan(b)^2 + 2*c*z*tan(b) - 2*z*tan(b) - c - tan(b)^2, z, 4))
 
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