如何实现Python识别处理企业微信pc版消息

Question

企业微信pc版的栏目中不定时会推送信息，这个信息为文本，如何接收信息就保存文本。

Answer 1

接受信息

@app.route('/blackcat/v1/receive_task', methods=['POST', 'GET'])
def receive():
    try:
        auth_verify = AuthVerify()
        if request.method == "POST":
            msg_signature = request.args.get('msg_signature')
            timestamp = request.args.get('timestamp')
            nonce = request.args.get('nonce')
            request_data = request.data
            param = auth_verify.verifi_content(msg_signature, timestamp, nonce, request_data)
            submit_task_receive.delay(param)
        if request.method == "GET":

建立一个对应消息处理机制，即收到什么信息，做什么处理
如发送消息
可用下面代码
发送信息

#! /usr/bin/env python
# -*- coding: UTF-8 -*-
 
import requests, sys
 
 
class SendWeiXinWork():
    def __init__(self):
        self.CORP_ID = "xxx"  # 企业号的标识
        self.SECRET = "xxx"  # 管理组凭证密钥
        self.AGENT_ID = xxx  # 应用ID
        self.token = self.get_token()
 
    def get_token(self):
        url = "https://qyapi.weixin.qq.com/cgi-bin/gettoken"
        data = {
            "corpid": self.CORP_ID,
            "corpsecret": self.SECRET
        }
        req = requests.get(url=url, params=data)
        res = req.json()
        if res['errmsg'] == 'ok':
            return res["access_token"]
        else:
            return res
 
    def send_message(self, to_user, content):
        url = "https://qyapi.weixin.qq.com/cgi-bin/message/send?access_token=%s" % self.token
        data = {
            # "touser": to_user,  # 发送个人就填用户账号
            "toparty": to_user,  # 发送组内成员就填部门ID
            "msgtype": "text",
            "agentid": self.AGENT_ID,
            "text": {"content": content},
            "safe": "0"
        }
 
        req = requests.post(url=url, json=data)
        res = req.json()
        if res['errmsg'] == 'ok':
            print("send message sucessed")
            return "send message sucessed"
        else:
            return res
 
 
if __name__ == '__main__':
    SendWeiXinWork = SendWeiXinWork()
    SendWeiXinWork.send_message("2", "测试a")