这道c++题哪位同学可以讲讲怎么运行啊

Question

class AA{
public:
  void f(){cout<<"AA";}
};

class BB:public AA{
public:
    BB(){cout<<"BB";}
};
class CC:public BB{
  public:
         void f(){BB::f();cout<<"CC";}
};
int main(){
AA aa,*p;
BB bb;
CC cc;
p=&cc;
p->f();
return 0;
}

Answer 1

调用默认构造函数，继承的时候构造函数会调用基类的构造函数，然后子类对象赋值给基类的指针，基类指针的函数调用是基类的~