函数指针类型传递的问题

Question

请问各位专家，这里经过函数运行的结果之后p和q本身的地址和指向对象的值都没有发生改变是为什么？

#include <iostream>
using namespace std;
void func1(int*, int*);
int main()
{
    int* p, * q, a = 1, b = 2;
    p = &a;
    q = &b;
    cout << p << "  " << *p << endl;
    cout << q << "  " << *q << endl;
    func1(p, q);
    cout << p <<"  "<< * p << endl;
    cout << q <<"  "<< * q << endl;
    
}
void func1(int* p, int*q)
{
    p = q;
    *p = *q;
    
}

运行结果：
000000752414FAA4 1
000000752414FAC4 2
000000752414FAA4 1
000000752414FAC4 2

Answer 1

• 这有个类似的问题, 你可以参考下: https://ask.csdn.net/questions/7632771