检查元素是否是没有正则表达式的数组中的元音

Question

Is there a better way to check if an element is a vowel in an array?

foreach($alphaArray as $alpha) {
    $ascii = ord($alpha); // convert each alpha to ascii

    if($ascii == 65 || $ascii == 69 || $ascii == 73 || $ascii == 79 || $ascii == 85
        || $ascii == 97 || $ascii == 101 || $ascii == 105 || $ascii == 111 || $ascii == 117) {
        $vowelArray[] = $alpha;

    } else {
        $consonantArray[] = $alpha;
    }
}

Teacher does not allow regEx.

Answer 1

This should work for you:

(Here i just use in_array() and strtouppper() to check if it is a vowel)

$vowels = array('A', 'E', 'I', 'O', 'U');

foreach($alphaArray as $alpha) {

    if(in_array(strtoupper($alpha), $vowels)) {
        $vowelArray[] = $alpha;
    } else {
        $consonantArray[] = $alpha;
    }

}