不能理解为什么不是叶子结点减一等于非叶子结点

Question

这个问题中叶子结点减一不等于非叶子节点吗
如果减一不等于非叶子节点的话，能给个反例

Answer 1

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在一棵二叉树中，如果叶子节点比非叶子节点多1，那么叶子节点减1就等于非叶子节点。 例如：

      1
     / \
    2   3
   / \
  4   5
      |
      6

在这棵二叉树中，叶子节点有4个，非叶子节点有3个，叶子节点减1等于3，等于非叶子节点的数量。但是，如果叶子节点比非叶子节点多2或更多，那么叶子节点减1就不等于非叶子节点了。 代码示例：

class Node:
    def __init__(self, val=None, left=None, right=None):
        self.val = val
        self.left = left
        self.right = right
def count_leaves_and_non_leaves(root):
    if not root:
        return 0, 0
    
    leaves_left, non_leaves_left = count_leaves_and_non_leaves(root.left)
    leaves_right, non_leaves_right = count_leaves_and_non_leaves(root.right)
    
    leaves = (1 if not root.left and not root.right else 0) + leaves_left + leaves_right
    non_leaves = (1 if root.left or root.right else 0) + non_leaves_left + non_leaves_right
    
    return leaves, non_leaves
root = Node(1)
root.left = Node(2)
root.right = Node(3)
root.left.left = Node(4)
root.left.right = Node(5)
root.left.right.right = Node(6)
leaves, non_leaves = count_leaves_and_non_leaves(root)
print(f"Leaves: {leaves}, Non-leaves: {non_leaves}")