dongluan1743 2017-02-13 17:19
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MySQL PHP:无法获得任何结果[重复]

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I was trying to just print the content of my MySQL Database with PHP.

This is how my database looks like:

mysql> show tables;
| Tables_in_myTable |
| users             |
1 row in set (0,00 sec)

mysql> select * from users;
| name       |
| Nick       |
1 row in set (0,00 sec)

My PHP code looks like this:

echo "HI"; //to see, that the php gets runned at all.

$connection = mysql_connect('localhost', 'root', ''); //The Blank string is the password

$query = "SELECT * FROM users"; 
$result = mysql_query($query);

echo "<table>"; 

while($row = mysql_fetch_array($result)){    
    echo "<tr><td>" . $row['name'] . "</td></tr>"; 

echo "</table>"; 


But on the website, the only output I get is


I checked the username, passwd and DB-Names in my PHP.

I'm running an apache2 Server on Ubuntu (Ubuntu Gnome, if that matters) 16.10 and the community version of MySQL

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  • dougezhua0017 2017-02-13 17:26

    mysql_select_db selects a database, yet you pass your table name as a parameter. Table name is different from database name. Check your database name using

    show databases;

    and use that instead of table name on mysql_select_db

    Also, mysql_* functions are deprecated, you need to use mysqli_* functions or PDO.

    It is also a bad idea to run queries like

    SELECT * FROM users

    it is better to select the columns you need explicitly, like

    SELECT name FROM users


    I was confused by the database name, which seems to be myTable indeed. The problem was that the deprecated functions were not found.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?



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