dongya8378 2017-01-30 11:13
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如何将'字符添加到表示PHP中WS调用的JSON的字符串中?

I am an abslolute beginner in PHP and moreover in Laravel framework (I came from Java).

I am finding the following problem trying to perform a Guzzle call to a REST web service:

if I do it using mocked creadential data it works fine:

    $response = $client->get('http://localhost:8080/Extranet/login',
        [
            'auth' => [
                'nobili.andrea@gmail.com',
                'pswd'
            ]
        ]);

    $dettagliLogin = json_decode($response->getBody());

    \Log::info('response: '.(json_encode($dettagliLogin)));

But trying to do in this way

    $response = $client->get('http://localhost:8080/Extranet/login',
        [
            'auth' => [
                //'nobili.andrea@gmail.com',
                //'pswd'
                $credentials['email'] . ','
                .$credentials['password']
            ]
        ]);

    $dettagliLogin = json_decode($response->getBody());

    \Log::info('response: '.(json_encode($dettagliLogin)));

it goes into error.

I think that maybe the problem could depend by the fact that the mocked credential contain the ' before and after username and password fields:

'nobili.andrea@gmail.com',
'pswd'

How can I insert it in my dynamic version of code?

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2条回答 默认 最新

  • dongyan3237 2017-01-30 11:16
    关注

    You need to perform like this:

       $response = $client->get('http://localhost:8080/Extranet/login',
            [
                'auth' => [
                    $credentials['email'],   // <=== don't concatinate the comma here
                    $credentials['password']
                ]
            ]);
    

    No, need to concatinate the array parameters.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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