doutan1857 2017-08-02 12:12
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将时间戳转换为另一种日期格式[重复]

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I have a date

  $myDate = "2017-07-31 06:12:51";

I wanted to convert this date into following format

  $result = "12/31/1969 - 07:33 PM"

I have used below function to convert specific date

  $result = date("m/d/Y - h:i A",$myDate);

It is converting in the format I want but everytime it is printing the below same date for differents timings.

  12/31/1969 - 07:33 PM

Which is wrong, Please suggest

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  • doubaran2438 2017-08-02 12:14
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    date() requires the second parameter to be a Unix timestamp. Use strtotime() to do this:

    $result = date("m/d/Y - h:i A", strtotime($myDate));
    

    Demo

    strtottime() requires a valid date format to work, but yours is so you won't have any problems.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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