PHP：如何在将数组项传递给函数时输出键本身？

Question

Given array item $array["first level"]["second LVL"], how can I get the key string second LVL itself, not the key-value-pair value?

More Detailed Example

I have an array item variable $array["address"]["city"] that I am passing to a function like so:

<?php

printKey( $array["address"]["city"] );

function printKey( $array_item ) {
    return "Output: " . keyValue(array_item);
}

?>

How can I get the key value string city itself from the array item $array["address"]["city"]?

I've seen array_search(), array_keys(), and key(), but none seem to do the trick without a for loop at the least.

EDIT / Clarification:

The problem is, for example, sometimes my function is passed $array["address"]["name"] and sometimes it passes $array["address"]["company"].

I need to be able to dynamically output Name: or Name:

Example function:

$array["address"]["name"] = "Andre";
$array["address"]["company"] = "StackNot";

function printITEMkeyAndValue( $arrayITEM ) {
    //It's not possible to do a for loop on just an item, right? It's just a string (?)
    return $array_item_key . ": " . $array_item_value;
}

echo printITEMkeyAndValue( $array["address"]["name"] );
echo printITEMkeyAndValue( $array["address"]["company"] );

Desired output:

Name: Andre
Company: StackNot

Answer 1

I understand what you want, but see when you call printKey function with a 2 value, it is not possible to find a key, because array does not exist in the function, the solution is to send the array and your item into the function and find it by search and then get the key.

<?php

$array["address"]["city"] = 2;

function printKey( $array, $item ) {
    foreach($array["address"] as $key =>$value){
        if ($value == $item){
            return "Output: " . $key;           
        }
    }
}

echo printKey($array, $array["address"]["city"]);