douxiong5438 2011-03-15 15:15
浏览 39
已采纳

多个AJAX请求功能合二为一?

I have pretty much the same Ajax Request call but I need to expand it to be more generic

See example Code: http://jsfiddle.net/2b8gR/6/

I have it working for Page A and want to use it for Page B, C, D, etc... but don't want to rewrite the function for every new Ajax request.

Most of the code will remain the same except:

  • input next/prev (page_a_next becomes page_b_next)
  • display page div (display_page_a_page becomes display_page_b_page)
  • display page number div (display_page_a_number becomes display_page_b_number)
  • ajax request url page name (url: 'page_a.php?page='+currentPageA, becomes url: 'page_b.php?page='+currentPageB,)

and so forth.

How do I make the Ajax call and elements more generic so I don't have to write this request multiple times?

NOTE: I need to be able to keep track of each page (A, B, C, etc...) it's currently displaying. And yes all of these are on the same page

HTML:

<!-- Page A -->
<div>
    <span>Page A</span>
    <input id="page_a_next" name="page_a_next" type="button" value="Next" data-inline="true" />
    <input id="page_a_prev" name="page_a_prev" type="button" value="Previous" data-inline="true" /> 
</div>   
<div id="display_page_a_page" name="display_page_a_page">
</div>
<div id="display_page_a_number" name="display_page_a_number">
</div>

<!-- Page B -->
<div>
    <span>Page B</span>
    <input id="page_b_next" name="page_b_next" type="button" value="Next" data-inline="true" />
    <input id="page_b_prev" name="page_b_prev" type="button" value="Previous" data-inline="true" /> 
</div>   
<div id="display_page_b_page" name="display_page_b_page">
</div>
<div id="display_page_b_number" name="display_page_b_number">
</div>

JS:

var currentPageA=1;
var totalPageA=113;
loadPageA();

$("#page_a_next, #page_a_prev").click(function(){
    currentPageA = ($(this).attr('id')=='page_a_next') ? currentPageA + 1 : currentPageA - 1;

    if(currentPageA<=0) {
        currentPageA=1;                
        $('#page_a_prev').attr('disabled','disabled');
    } else if(currentPageA==114) {
        currentPageA=113;
        $('#page_a_next').attr('disabled','disabled');
    } else {
        loadPageA();
    }                
});

function loadPageA(){
    $('#page_a_next').attr('disabled','disabled');
    $('#page_a_prev').attr('disabled','disabled');

    $.ajax({
        url: 'page_a.php?page='+currentPageA,
        type: 'POST',
        error : function (){ alert('Error'); }, 
        success: function (data) {
            $('#display_page_a_number').html(currentPageA + ' of ' + totalPageA);
            $('#display_page_a_page').html(data);
            $('#page_a_next').attr('disabled','');
            $('#page_a_prev').attr('disabled','');
        }
    });
}
  • 写回答

3条回答 默认 最新

  • douji3623 2011-03-15 15:38
    关注

    The key here is not just to generalize your JS, but to also generalize your HTML. You must also change your currentPageA and totalPageA variables to array so they can hold more than one value.

    See my Demo: http://jsfiddle.net/Jaybles/b2uRd/

    HTML

    <!-- Page A -->
    <div>
        <span>Page A</span>
        <input class='pageButton' id="page_a_next" name="page_a_next" type="button" value="Next" data-inline="true"/>
        <input class='pageButton' id="page_a_prev" name="page_a_prev" type="button" value="Previous" data-inline="true" /> 
    </div>   
    <div id="display_page_a_page" name="display_page_a_page">
    </div>
    <div id="display_page_a_number" name="display_page_a_number">
    </div>
    
    <!-- Page B -->
    <div>
        <span>Page B</span>
        <input class='pageButton' id="page_b_next" name="page_b_next" type="button" value="Next" data-inline="true" />
        <input class='pageButton' id="page_b_prev" name="page_b_prev" type="button" value="Previous" data-inline="true" /> 
    </div>   
    <div id="display_page_b_page" name="display_page_b_page">
    </div>
    <div id="display_page_b_number" name="display_page_b_number">
    </div>
    

    JS

    var currentPage = {'a':1, 'b':1}; //Should go from A to Z
    var totalPage = {'a':113, 'b':115}; //Should go from A to Z
    
    $(".pageButton").click(function(){
        var a = $(this).attr('name').split("_");
        var page = a[1];
        var dir = a[2];
        currentPage[page]  = (dir=='next') ? currentPage[page] + 1 : currentPage[page] - 1;
    
        if(currentPage[page]<=0) {
            currentPage[page]=1;                
            $('#page_' + page + '_prev').attr('disabled','disabled');
        } else if(currentPage[page] > totalPage[page]) {
            currentPage[page]=totalPage[page];
            $('#page_' + page + '_next').attr('disabled','disabled');
        } else {
            loadPage(page);
        }                
    });
    
    loadPage('a');
    
    function loadPage(page){
        $('#page_' + page + '_next').attr('disabled','disabled');
        $('#page_' + page + '_prev').attr('disabled','disabled');
    
        $.ajax({
            url: 'page_' + page + '.php?page='+currentPage[page],
            type: 'POST',
            error : function (){ document.title='error'; }, 
            success: function (data) {
                $('#display_page_' + page + '_number').html(currentPage[page]+ ' of ' + totalPage[page]);
                $('#display_page_' + page + '_page').html(data);
                $('#page_' + page + '_next').attr('disabled','');
                $('#page_' + page + '_prev').attr('disabled','');
            }
        });
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(2条)

报告相同问题?

悬赏问题

  • ¥15 下图接收小电路,谁知道原理
  • ¥15 装 pytorch 的时候出了好多问题,遇到这种情况怎么处理?
  • ¥20 IOS游览器某宝手机网页版自动立即购买JavaScript脚本
  • ¥15 手机接入宽带网线,如何释放宽带全部速度
  • ¥30 关于#r语言#的问题:如何对R语言中mfgarch包中构建的garch-midas模型进行样本内长期波动率预测和样本外长期波动率预测
  • ¥15 ETLCloud 处理json多层级问题
  • ¥15 matlab中使用gurobi时报错
  • ¥15 这个主板怎么能扩出一两个sata口
  • ¥15 不是,这到底错哪儿了😭
  • ¥15 2020长安杯与连接网探