drnx3715 2014-02-19 10:16
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如何获取图像并在下一页显示？

I am implementing a form to get personal details of user and an image of user for DP. How do i display it on next page if data is submitted correctly.

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  • doucao1066 2014-02-19 10:27
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    This can help you,

    The upload form. 

      <html>
  <head><title>File Upload To Database</title></head>
  <body>
  <h2>Please Choose a File and click Submit</h2>
  <form enctype="multipart/form-data" action="<?php echo htmlentities($_SERVER['PHP_SELF']);?>" method="post">
  <input type="hidden" name="MAX_FILE_SIZE" value="99999999" />
  <div><input name="userfile" type="file" /></div>
  <div><input type="submit" value="Submit" /></div>
  </form>

</body></html>

    Uploading the image.

    <?php
/*** check if a file was submitted ***/
if(!isset($_FILES['userfile']))
    {
    echo '<p>Please select a file</p>';
    }
else
    {
    try    {
        upload();
        /*** give praise and thanks to the php gods ***/
        echo '<p>Thank you for submitting</p>';
        }
    catch(Exception $e)
        {
        echo '<h4>'.$e->getMessage().'</h4>';
        }
    }
?>

    The upload function

    <?php
/**
 *
 * the upload function
 * 
 * @access public
 *
 * @return void
 *
 */
function upload(){
/*** check if a file was uploaded ***/
if(is_uploaded_file($_FILES['userfile']['tmp_name']) && getimagesize($_FILES['userfile']['tmp_name']) != false)
    {
    /***  get the image info. ***/
    $size = getimagesize($_FILES['userfile']['tmp_name']);
    /*** assign our variables ***/
    $type = $size['mime'];
    $imgfp = fopen($_FILES['userfile']['tmp_name'], 'rb');
    $size = $size[3];
    $name = $_FILES['userfile']['name'];
    $maxsize = 99999999;


    /***  check the file is less than the maximum file size ***/
    if($_FILES['userfile']['size'] < $maxsize )
        {
        /*** connect to db ***/
        $dbh = new PDO("mysql:host=localhost;dbname=testblob", 'username', 'password');

                /*** set the error mode ***/
                $dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);

            /*** our sql query ***/
        $stmt = $dbh->prepare("INSERT INTO testblob (image_type ,image, image_size, image_name) VALUES (? ,?, ?, ?)");

        /*** bind the params ***/
        $stmt->bindParam(1, $type);
        $stmt->bindParam(2, $imgfp, PDO::PARAM_LOB);
        $stmt->bindParam(3, $size);
        $stmt->bindParam(4, $name);

        /*** execute the query ***/
        $stmt->execute();
        }
    else
        {
        /*** throw an exception is image is not of type ***/
        throw new Exception("File Size Error");
        }
    }
else
    {
    // if the file is not less than the maximum allowed, print an error
    throw new Exception("Unsupported Image Format!");
    }
}
?>

    Displaying the image

    <?php

/*** some basic sanity checks ***/
if(filter_has_var(INPUT_GET, "image_id") !== false && filter_input(INPUT_GET, 'image_id', FILTER_VALIDATE_INT) !== false)
    {
    /*** assign the image id ***/
    $image_id = filter_input(INPUT_GET, "image_id", FILTER_SANITIZE_NUMBER_INT);
    try     {
        /*** connect to the database ***/
        $dbh = new PDO("mysql:host=localhost;dbname=testblob", 'username', 'password');

        /*** set the PDO error mode to exception ***/
        $dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);

        /*** The sql statement ***/
        $sql = "SELECT image, image_type FROM testblob WHERE image_id=$image_id";

        /*** prepare the sql ***/
        $stmt = $dbh->prepare($sql);

        /*** exceute the query ***/
        $stmt->execute(); 

        /*** set the fetch mode to associative array ***/
        $stmt->setFetchMode(PDO::FETCH_ASSOC);

        /*** set the header for the image ***/
        $array = $stmt->fetch();

        /*** check we have a single image and type ***/
        if(sizeof($array) == 2)
            {
            /*** set the headers and display the image ***/
            header("Content-type: ".$array['image_type']);

            /*** output the image ***/
            echo $array['image'];
            }
        else
            {
            throw new Exception("Out of bounds Error");
            }
        }
    catch(PDOException $e)
        {
        echo $e->getMessage();
        }
    catch(Exception $e)
        {
        echo $e->getMessage();
        }
        }
  else
        {
        echo 'Please use a real id number';
        }
?>

    If you want any other information, you canrefer to this link:

    http://www.phpro.org/tutorials/Storing-Images-in-MySQL-with-PHP.html
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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