dqde43215 2015-11-06 17:06
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如何在模态中返回提交表单的结果

I have a contact form on contactpage1.php (department, name, email, message). When it is submitted the form 'action' is contactpage2.php which validates the data and either return error messages or emails the message.

Rather than having to go to contactpage2.php, I would prefer to keep everything on one page and have contactpage2.php open in a modal.

How would I do that?

So far, I've seen lots of example of clicking a button to open a modal with the contact form but that's not what I am after. Can I do it as described above?

I'm using Bootstrap modals elsewhere on the site.

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  • doufan9805 2016-02-02 21:35
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    Answer taken from a comment by Shehary

    Here are the steps according to your question

    1. you have form on contactpage1.php.
    2. Submit it with Ajax.
    3. show modal in Ajax success function with $('#selector').modal('show');

    You can also bind the element in modal to show the message in modal, so what you need is the Ajax Method and all other steps can be taken care inside Ajax call.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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