dtra49684 2015-09-02 23:29
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尝试创建动态json列表/数组时获取字符串

I am trying to make a dynamic JSON array in PHP, however when I try to do so it returns "Array". Here is the code I am currently using:

        <?php
        require '../../scripts/connect.php';    

    $array = '';
    if($result = $db->query("SELECT * FROM art") or die ($db->error)){
      if($count = $result->num_rows) {
             while($row = $result->fetch_object()){

        $array .= array(
            'title'    => $row->title,
            'image'     => "http://www.thewebsite.com/img/2.jpg",
            'rating'     => 7.7,
            'releaseYear'     => 2003,
            'genre'  => array(
                '0'        => $row->category,
                '1'        => $row->subcategory
            )
        );
       }
      }
     }

    echo json_encode($array);





    ?>

Can anyone suggest how I might go about fixing this? And if anyone has suggestions about creating a dynamic JSON array, some help would be much appreciated.

  • 写回答

1条回答 默认 最新

  • dongmi5177 2015-09-02 23:36
    关注

    Change your declaration of $array to be an array:

    $array = array();
    

    Then in your while loop, when you add the new array to $array, push it like this:

    $array[] = array('title'=>$row->title, etc...)
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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