dpqjvoq9033 2015-12-03 01:01
浏览 7

大家好我想通过在e之间实现下拉菜单来使php表更好看

I am trying to make a php table look more nicer by implementing a drop down menu between its rows , my code for creating a table is the following

echo "<table class=box  border=1px>
<div id=<wrapper>
<tr>
<th>Zone</th>
<th>Rownumber</th>
</tr>";

echo "<form action=selectsits.php enctype=multipart/form-data method=post>";
while($record=mysql_fetch_array($availablesitsdata) )  {
echo '<tr>';
echo '<select name=cat_id>
<option value="a">aa</option>
<option value="b">bb</option>     
      </select>
    </td>';
echo "<td>" . $record['Zone']  . "</td>";

echo"</tr>";
}
echo "</form>";

but the drop down menus are outside the table and not inside. Does anyone has any idea how to fix this?

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1条回答 默认 最新

  • duanhe6799 2015-12-03 01:03
    关注

    You havent table close tag. You need a in your code.

    I corrected your code a little bit:

    echo '<table class="box"  style="border: 1px">'
    <div id="wrapper">
    <tr>
    <th>Zone</th>
    <th>Rownumber</th>
    </tr>";
    
        echo "<form action="selectsits.php" enctype=multipart/form-data method=post>";
    while($record=mysql_fetch_array($availablesitsdata) )  {
    echo '<tr>';
    echo '<select name="cat_id">'.
    '<option value="a">aa</option>'.
    '<option value="b">bb</option>'.
          '</select>'.
        '</td>';
    echo "<td>" . $record['Zone']  . "</td>";
    
    echo"</tr>";
    }
    echo "</form>";
    echo "</div>";
    echo "</table>";
    

    But it is very ugly code.

    评论

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